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AP, BQ, CR r the diameters of the circumcircle of triangle ABC. Let a1, a2, a3, a be areas of triangles BPC, CQA, ARB and ABC respectively. Then i) a1 =

 ii) a1+ a2+a3,=

iii) BP2 + CQ2 + AR2 =


6 years ago


Answers : (1)




BP2 =AP2 -AB2

     =4R2 -c2


CP2 =AP2 -AC2

     =4R2 -b2

We know  Δ =abc/4R

trianble BPC also have same circumradius

so a1=BC*CP*PB/4R

        =a V(4R2 -b2) V(4R2 -c2) /4R

similerly you can find a2 and a2

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6 years ago

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