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```        AP, BQ, CR r the diameters of the circumcircle of triangle ABC. Let a1, a2, a3, a be areas of triangles BPC, CQA, ARB and ABC respectively. Then i) a1 =
ii) a1+ a2+a3,=
iii) BP2 + CQ2 + AR2 =
```
7 years ago

147 Points
```										Dear

BP2 =AP2 -AB2
=4R2 -c2
similerly
CP2 =AP2 -AC2
=4R2 -b2
We know  Δ =abc/4R
trianble BPC also have same circumradius
so a1=BC*CP*PB/4R
=a V(4R2 -b2) V(4R2 -c2) /4R
similerly you can find a2 and a2
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```
7 years ago
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