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Find the value of a for which the eqn
4 cosec 2 (π (a+x) ) + a2 - 4a = 0 has a real solution.
Dear Sanchit
4 cosec 2 (π (a+x) ) + a2 - 4a = 0
4 cosec 2 (π (a+x) ) =- a2 + 4a
L .H .S is always greater than 4 so for real solution
-a2 + 4a ≥4
or (a-2)2≤0
so only a=2 is possible
All the best. Regards, Askiitians Experts Badiuddin
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