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Sanchit Gupta Grade: 12
        

Find the value of a for which the eqn 


4 cosec 2 (π (a+x) ) + a2 - 4a = 0 has a real solution.

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Sanchit


4 cosec 2 (π (a+x) ) + a2 - 4a = 0


4 cosec 2 (π (a+x) ) =- a2 + 4a 


L .H .S is always greater than 4 so for real solution


 -a2 + 4a ≥4


or (a-2)2≤0


so only a=2 is possible





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Badiuddin

7 years ago
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