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pallavi pradeep bhardwaj Grade: 12
        

In a right angled triangel the hypotenuse is four times as long as the perpendicular drawn to it from the opposite vertex .One of the acute angel is

7 years ago

Answers : (1)

Ramesh V
70 Points
										

5674-390_5850_untitled.JPG


c2 = h2 + (a-x)2


b2 = h2 + x2


on adding, we have  2h2 + x2 + (a-x)2 = a2 ..(1)


also a = 4h  and cos B = b/a = x/b


so x = b2/a


on solving (1), we have  h2 + x2 -4hx = 0


substituting above gives


b4 + a4/16 -a2.b2 =0 .. (2)


as cos B = b/a


on solving eqn. (2) we have ,  Cos2B = 0.933 or 0.067


Cos B = 0.966 or 0.259


B = 15 or 75 degrees


as B is acute , B is 15 degrees


--


regards


Ramesh



7 years ago
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