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nagaraju kondeti Grade:
        

sin30=

5 years ago

Answers : (2)

Kurma Anudeep
30 Points
										

sin30=sin45-sin15=1/2

5 years ago
Ramya Ananth
4 Points
										

Draw an equilateral triangle ABC.




Draw a perpendicular from A to BC intersecting BC at D

AB = AC (sides of an equilateral trianlge are equal)

Angle ADB = Angle ADC = 90

AD = AD

ΔADB ≅ ΔADC (RHS postulate)



BD = DC = (1/2)BC = (1/2)AB (congruence of triangles and sides of an equilateral triangle are equal)



Angle ABD = AngleDAC = 60/2 = 30 (congruence of triangles)



sinBAD = BD/AB = 1/2

sin(30) = 1/2
5 years ago
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