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If m= sin6x + cos6x, then m belongs to the interval

(a) [7/8, 5/4]  (b) [1/2 , 5/8]  (c) [1/4,  1]

Explain pls...

4 years ago


Answers : (1)



as a3+b3=(a+b)(a2-ab+b2)

we know that,





we know 0<=sin2A<=1,

so -1<=-sin22x<=0 multiply with -1,

-3/4<=-3/4(sin22x)<=0 multiply with 3/4,

1/4<=1-3/4(sin22x)<=1 add 1,


therefore "m" belongs to[1,1/4].

4 years ago

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