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```        In a triangle ABC , find the least value of,
cot A/2 * cot B/2 * cot C/2 * cos A/2 * cos B/2 * cos C/2```
8 years ago

Ramesh V
70 Points
```										here the least value is obtained when triangle is eqilateral triangle:
A=B=C=60o
cot A/2 * cot B/2 * cot C/2 * cos A/2 * cos B/2 * cos C/2 =  (cot 30 * cos30 )3
= 3/2
--
Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best.Regards,Ramesh   IIT Kgp - 05 batch
```
8 years ago
Moni RS
18 Points
```										Sir, why is the triangle considered to be equilateral, is there any reason behind that, or how can conclude such things sir....plz help me??
```
8 years ago
Ramesh V
70 Points
```										since the least value, which we want to find - applies for all triangles ( be a scalene,obtuse,right angled); the simplest case can be an equilateral triangle.
I suggest when ever, if an objective question comes on propoeties of triangles, take the case of an equilateral triangle - and u shld find the answer in one of options

```
8 years ago
Moni RS
18 Points
```										Sir isn't the final answer (3/2)^3
```
8 years ago
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