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Moni RS Grade: 11
        

In a triangle ABC , find the least value of,


 cot A/2 * cot B/2 * cot C/2 * cos A/2 * cos B/2 * cos C/2

8 years ago

Answers : (4)

Ramesh V
70 Points
										

here the least value is obtained when triangle is eqilateral triangle:


A=B=C=60o


cot A/2 * cot B/2 * cot C/2 * cos A/2 * cos B/2 * cos C/2 =  (cot 30 * cos30 )


= 3/2


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Regards,
Ramesh  
IIT Kgp - 05 batch




8 years ago
Moni RS
18 Points
										

Sir, why is the triangle considered to be equilateral, is there any reason behind that, or how can conclude such things sir....plz help me??

8 years ago
Ramesh V
70 Points
										

since the least value, which we want to find - applies for all triangles ( be a scalene,obtuse,right angled); the simplest case can be an equilateral triangle.


I suggest when ever, if an objective question comes on propoeties of triangles, take the case of an equilateral triangle - and u shld find the answer in one of options



8 years ago
Moni RS
18 Points
										

Sir isn't the final answer (3/2)^3

8 years ago
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