no. of solutions(x,y) to mod(y) = sinx ; y = cos inverse(cos x) where -2pi

Question

no. of solutions(x,y) to mod(y) = sinx ; y = cos inverse(cos x) where -2pi <= x <=2pi A.1 B.2 C.3 D.4

Aman Bansal · Answer

Dear Naman,

Only two solutions are possible.

Best of Luck

Plz Approve the answer...!!!!

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Aman Bansal

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naman kumar · Answer

BUT THE ANSWER GIVEN IS 3 IS IT WRONG ACTUALLY I GOT 1 AS THE ANSWER

Priyank · Answer

3...draw d graph...3 solutions having abscissa 0 2pi -2pi respectively......................... ............... ............. ......... .... .... .....

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no. of solutions(x,y) to mod(y) = sinx ; y = cos inverse(cos x) where -2pi A.1 B.2 C.3 D.4

no. of solutions(x,y) to mod(y) = sinx ; y = cos inverse(cos x) where -2pi <= x <=2pi
A.1
B.2
C.3
D.4

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