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Mayank Jain Grade: 11
        


I cudnt solve these Question ......can u help me out plzz:-


Q.1 The Smallest Positive root of the equation tan(x) - x = 0, lies in :-


a) (0,pi/2)


b) (pi/2, pi)


c) (pi, 3pi/2)


d) (3pi/2, 2pi)


 


Q.2 The number of roots of the equation x + 2tan (x) = pi/2 in the interval [0, 2pi] is


a) 1


b)2


c)3


d) infinite


 


Thanks!


6 years ago

Answers : (3)

AKASH GOYAL AskiitiansExpert-IITD
419 Points
										

Dear Ashray


See the pic for the solution


 


All the best.                                                           


AKASH GOYAL


AskiitiansExpert-IIT Delhi


 


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795_23499_Photo-0158.jpg

6 years ago
Mir Noaman Ali IIT-Roorkee
57 Points
										

answer to first question = as they asked about smallest positive root so tan x cant be -ve as x is always + vs nd in 0 ,pi/2 tan x is always gr8 dan x ... but from pi to 3pi/2 tan x goes from 0 to infinity  so it will at some point of time in 3rd quadrant will be = x ......... alternative method is by drawing graphs u will easily get it ............................................................................. ANSWER TO 2ND QUESTION  2TANX = PI/2 - X ........... PI/2 - X IS A STRAIGHT LINE SO U CAN DRAW IT ND THEN 2 TAN X GRAPH PLEASE DRAW IT U CAN OBSERVE THAT THE GRAPHS INTERSECTS AT 3 POSITIONS ONE EACH IN FRST 2ND ND 4TH QUADRANTS .THANK YOU PLEASE APPROVE MY ANSWER IF U LIKE IT

6 years ago
Mayank Jain
37 Points
										

Thanks a lot !

6 years ago
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