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```
If in a triangle ABC, sinA, sinB, sinC are in AP then show that
tan A/2 tan C/2 = 1/3
I have solved above problem as follows:
2b = a + c (Given)
2b + b = a + c + b
3b = 2s
3b + s = 2s + s
3(s - b) = s
(s - b)/s = 1/3
Since (s - b)/s = tan A/2 tan C/2
It is proved that tan A/2 tan C/2 = 1/3

My question is can we solve the problem starting from  2 sinB = sinA + sinC and without using 2b = a + c
```
6 years ago

SAGAR SINGH - IIT DELHI
879 Points
```										Dear student,
No you have to use 2b=a+c anyhow to prove it...

All the best.
Win exciting gifts by                                                                                                  answering     the           questions    on                     Discussion                Forum.      So           help                          discuss            any                        query      on                    askiitians          forum     and               become     an             Elite                      Expert           League                           askiitian.

Sagar Singh
B.Tech, IIT Delhi

```
6 years ago
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