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ravi teja Grade:
        

solve the system


 


sinx+cosy=1


 


cos2x-cos2y=1

6 years ago

Answers : (2)

vikas askiitian expert
510 Points
										

cos2x = 1-2sin2x                ......1


cos2y = 2cos2y-1              .........2


we have , cos2x-cos2y = 1


so , after putting  1 & 2 in above eq we get


 2(sin2x + cos2y) = 1


  sin2x+cos2y = 1/2            ...............3


 sinx+cosy = 1        .......................4         (given)


now ,


           (sinx+cosy)2 = sin2x + cos2x + 2sinxcosy


                   12  =  1/2 + 2sinxcosy


                  sinxcosy = 1/4       ................5


now from 4 & 5


                  sinx(1-sinx) = 1/4


                   (2sinx-1)2 = 0


        sinx= 1/2                                         cosy = 1/2


         x = npi +(-1)n (pi/6)                           y = 2npi +(-) (pi/3)

6 years ago
lits goyal
31 Points
										

sinx=.5


cosy=.5


 use cos2x=2cos squarex -1 and eliminate cos x.

6 years ago
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