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```        if   A + B =225
prove that
(cotA.cotB)/[(1 + cotA)(1 + cotB)] = 1/2

```
7 years ago

510 Points
```										(COTACOTB)/[(1+COTA)(1+COTB)] = 1/2
TAKING LHS

= (COTACOTB)/[1+COTACOTB +COTA+COTB] ...................1

NOW
COT(A+B)=COTACOTB - 1/COTA+COTB
A+B = 225 (GIVEN)
SO
COT225 = COTACOTB - 1/COTA+COTB
1 = COTACOTB-1/COTA+COTB                                                  (COT225=1)
COTA + COTB =COTACOTB - 1 ......................2
PUTTING 2 IN 1 WE GET
LHS= COTACOTB/2COTACOTB
=1/2 = RHS
HENCE PROVED
```
7 years ago
sumanth
32 Points
```										 (COTACOTB)/[(1+COTA)(1+COTB)] = 1/2 TAKING LHS    = (COTACOTB)/[1+COTACOTB +COTA+COTB] ...................1   NOW COT(A+B)=COTACOTB - 1/COTA+COTB A+B = 225 (GIVEN) SO       COT225 = COTACOTB - 1/COTA+COTB       1 = COTACOTB-1/COTA+COTB                                                  (COT225=1)   COTA + COTB =COTACOTB - 1 ......................2 PUTTING 2 IN 1 WE GET    LHS= COTACOTB/2COTACOTB         =1/2 = RHS HENCE PROVED
```
2 years ago
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