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paradox xyz cool Grade: 11
```        prove that:
sin2(n + 1)A - sin2nA = sin(2n + 1)A.sinA```
7 years ago

## Answers : (2)

vikas askiitian expert
510 Points
```										sin2(n+1)A - sin2nA = sin(2n+1)A.sinA
we have formula sin2a - sin2b =sin(a-b)sin(a+b)
therefore
sin2(n+1)A - sin2nA=sin[(n+1)A+nA].sin[(n+1)A-nA]
=sin(2n+1)A.sinA =RHS
hence proved
```
7 years ago
madhu voleti
44 Points
```										sin^2(n + 1)A - sin^2nA = sin(2n + 1)A.sinASolution:-    L.H.S:-sin^2(n + 1)A - sin^2nA =        Sin[(n+1)A+nA].Sin[(n+1)A-nA]        ["a^2-b^2=(a+b)(a-b)"]        =Sin[nA+A+nA].Sin[nA+A-nA]        =Sin[A(n+1+n)].SinA        =Sin(2n+1)A.SinA=R.H.S

Thank You!!!!!!!!!!!!!!!!
Wish You Happy learning of trignometry..............
```
7 years ago
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