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```
Find the value of a for which   4cosec2  ( π (a + x)) +a2 - 4a = 0 has a real solution. ```
6 years ago

30 Points
```										Dear Nirabhra,Solution:- 4cosec2(n(a+x)) + a2 - 4a =0
[4cosec2(n(a+x)) -4]  + (a2 - 4a + 4) =0
4[cosec2(n(a+x)) -1]  + (a-2)2 =0
[2cot(n(a+x))]2 + (a-2)2 =0 which means a =2 and cot(n(a+x)) =0
Ans: a= 2Please feel free to post as many doubts on our discussion forum as you can. If you find any questionDifficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.All the best Nirabhra!!!
```
6 years ago
kirankumar kishor
31 Points
```
Dear Nirabhra,Solution:- 4cosec2(n(a+x)) + a2 - 4a =0
[4cosec2(n(a+x)) -4]  + (a2 - 4a + 4) =0
4[cosec2(n(a+x)) -1]  + (a-2)2 =0
[2cot(n(a+x))]2 + (a-2)2 =0 which means a =2 and cot(n(a+x)) =0

```
6 years ago
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