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```        min value of
secA + secB + secC is............
```
7 years ago

74 Points
```										Hii Piyush

Look  in case of triangle...

cosA + cosB + cosC >= 3/2    ( as A + B + C = 180 )

Now apply AM>GM   =>   (cosA + cosB + cosC)/3  >=  ( cosA.cosB.cosC)^1/3

1/2 >= (cosA.cosB.cosC)^1/3     =>   secA.secB.secC >= 8

Now Again apply AM>GM

(secA + secB + secC)/3 >= (secA.secB.secC)^1/3

so for minimum value of  secA + secB + secC  ..put secA.secB.secC = minimum i.e = 8

So...secA + secB + secC =  3 X (8)^1/3 = 6  ans

I hope you get it

Regards
Yagya
```
7 years ago
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