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Hemanth Sai Grade: 11
        

if sinA+sinB= root3(cos B-cos A) then sin3B+sin3A =

6 years ago

Answers : (1)

Askiitians_Expert Yagyadutt
askIITians Faculty
74 Points
										

Hello Hemanth ....


 


sinA + sinB = root(3) cosB - root(3)cosA


 


Divide by 2 both side


 


sinA / 2  + sinB / 2  = root(3).cosB/2 - root(3).cosA/2


 


1/2 . sinA  + root(3)/2 .cosA  =  root(3)/2 . cos(B)  - 1/2 . sin(B)


 


sin(A + 60)  = cos(B + 30)  =>  sin(A+60) = sin ( 60 - B )


 


so finaly  A + 60 = 60 - B


 


so A = -B


 


Therefore   Sin3B + sin3A  =  0  


 


I hope i have answered you :)


 


Regards


 


Yagya


askiitians_expert

6 years ago
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