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vivek gupta Grade:
        

The angle of elevation of the top of a tower 30 m high, from two points on the level ground on its opposite sides are 45 degrees and 60 degrees. What is the distance between the two points?

8 years ago

Answers : (1)

raj kaushik
26 Points
										

CHECK OUT THIS SOLUTION  !!!! 


Let OT be te tower.






Therefore, Height of tower = OT = 30 m

Let A and B be the two points on the level ground on the opposite side of tower OT.



Then,


angle of elevation from A = Trigonometric RatiosTAO = 45o

and angle of elevation from B = Trigonometric RatiosTBO = 60o

Distance between AB = AO + OB = x + y (say)


Now, in right triangle ATO,

tan 45o = OT/AO =30/x         

=> x =  30/tan
45o  = 30 m


and in right traingle BTO

tan 60o =  OT/OB =30/y         


=> y = Trigonometric identities = 17.32 m




Hence, the required distance = x + y = 30 + 17.32 = 47.32 m


 

8 years ago
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