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```				   The angle of elevation of the top of a tower 30 m high, from two points on the level ground on its opposite sides are 45 degrees and 60 degrees. What is the distance between the two points?
```

7 years ago

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```										CHECK OUT THIS SOLUTION  !!!!
Let OT be te tower.

Therefore, Height of tower = OT = 30 m
Let A and B be the two points on the level ground on the opposite side of tower OT.

Then,
angle of elevation from A = TAO = 45o
and angle of elevation from B = TBO = 60o
Distance between AB = AO + OB = x + y (say)
Now, in right triangle ATO,
tan 45o = OT/AO =30/x
=> x =  30/tan45o  = 30 m
and in right traingle BTO
tan 60o =  OT/OB =30/y

=> y =  = 17.32 m

Hence, the required distance = x + y = 30 + 17.32 = 47.32 m

```
7 years ago

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