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```				   CosA-SinA+1/CosA+SinA-1=CosecA+CotA

```

6 years ago

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```										(cosA-sinA)+1/(cosA+sinA)-1
taking conjugate
(cosA-sinA)+1/(cosA+sinA)-1  *  (cosA+sinA)+1/(cosA+sinA)+1

multiplying we get
=cos2A-sin2A+2cosA+1/2sinAcosA
=cos2A-sin2A+2cosA+sin2A+cos2A/2sinAcosA
on solving we get

=2cos2A+2cosA/2sinAcosA
=taking 2 common and divided

we get

=cosA+cos2A/sinAcosA

we can alsom write in the form of
cosA/sinAcosA  +cos2A/sinAcosA

on  solving we get
CosecA+cotA =R.H.S

by swapnil sudhir

```
6 years ago

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