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`        show that:tan(x+a)/tan(x-a) cannot lie between the values tan square(pie/4-a) and tan square(pie/4+a)`
7 years ago

147 Points
```										Dear ravi
let y  = tan(x+a) /tan(x-a)
=tan{(x-∏/4) +(∏/4 +a)} / tan{( x-∏/4) + (∏/4-a)}
let tan(x-∏/4) =X
tan(∏/4 +a) =c
tan(∏/4 -a) =d

now open the expression
y =[(x+c)/(1-xc)] * [(1-xd)/(x+d)]
cross multiply and simplyfy
x2(d-yc) +x(y-1)(1-cd) +(yd-c) =0
for this function have real value discrimnant must be greater than zero
D≥0
put the discrimnant greater than zero you will get the desired result
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7 years ago
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