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if sinx+sin2x=2
then find,cos2x+cos4x
Hi Vishwa Sharma
sinx+sin2x=2
=>sinx+sin2x-2=0
=>(sinx-1)(sinx+2)=0
=>sinx=1 or sinx=-2
We know that sinx cannot be equal to -2.Hence rejaecting sinx=-2
Therefore, sinx=1 =>x=pi/2
cos2x+cos4x=xos2pi/2 + cos4pi/2 =0
=>sinx=1+1-sin2x
=>sinx=1+cos2x
=>cos2x=sinx-1
now,
cos2x+cos4x
=cos2x+(sinx-1)2
=cos2x+sin2x-2sinx+1
=1-2sinx+1
=2(1-sinx)
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