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if sinx+sin2x=2

then find,cos2x+cos4x

6 years ago

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### Answers : (1)

Ans:
$sin^{2}x + sinx = 2$
$(sinx+2)(sinx-1) = 0$
$sinx = 1$
is the only solution.
$x = n\pi \pm \frac{\pi }{2}$
$cos2x + cos4x = cos2(n\pi \pm \frac{\pi }{2}) + cos4(n\pi \pm \frac{\pi }{2})$
$cos2x + cos4x = cos(2n\pi \pm \pi ) + cos(4n\pi \pm 2\pi ) = -1 + 1 = 0$
Thanks & Regards
Jitender Singh
IIT Delhi
2 years ago

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