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```        question from s.l.loney page no. 130
question no. 8 and 9.```
7 years ago

147 Points
```										Dear neeraj
cos(π/15) .cos(2π/15) .cos(3π/15) .cos(4π/15) .cos(5π/15) .cos(6π/15) .cos(7π/15)
=cos(π/15) .cos(2π/15) .cos(π- 12π/15) .cos(4π/15) .cos(π/3) .cos(6π/15)  .cos(π-8π/15)
={cos(π/15) .cos(2π/15) .cos(4π/15) .cos(π-8π/15) }.{cos(π/3)}.{cos(6π/15).cos(8π/15)}
use the formula
=-1/24  * 1/2 * -1/22
=1/27
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get youthe answer and detailed  solution very  quickly. We are all IITians and here to help you in your IIT JEE preparation.All the best. Regards,Askiitians ExpertsBadiuddin
```
7 years ago
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