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```
If in triangle ABC, AD is the altitude from A. given b>c, angle C =23degree & AD =abc / b^2-c^2.
then angle B equal to?
```
7 years ago

28 Points
```										Dear Nehal,
or sinB=ab/(b² - c²)
or sinB=sinA sinB/sin(B+C) sin(B-C)
or sinB=sinAsinB/sinAsin(B-C)
or sin(B-C)=1=sin90°
or B-C=90°
Hence B=113°(ans)

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SOUMYAJIT IIT_KHARAGPUR
```
7 years ago
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