1-sin a /1+ sin a = (sec a – tan a) 2 prove lhs = rhs

Question

Sourabh Singh · Answer

Hiii

you can use the expansion first on the right hand side to convert it into ((1- sinA)/CosA)² and then write Cos² A as 1- Sin² A and then cancel out the common factors to get it equal to the LHS.

Hence LHS = RHS is proved.

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1-sin a /1+ sin a = (sec a – tan a) 2 prove lhs = rhs

1-sin a /1+ sin a = (sec a – tan a)² prove lhs = rhs

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1-sin a /1+ sin a = (sec a – tan a) 2 prove lhs = rhs

1-sin a /1+ sin a = (sec a – tan a)2 prove lhs = rhs

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1-sin a /1+ sin a = (sec a – tan a)² prove lhs = rhs