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sai teja Grade: 11
        
1+sec(theta)-tan(theta)/ 1+sec(theta)+tan(theta) =
 
and given options are 
  1. 1-cos(theta)/sin(theta)
  2. 1-sin(theta)/cos(theta)
  3. 1+cos(theta)/sin(theta)
  4. 1+sin(theta)/cos(theta)
                    
2 years ago

Answers : (1)

Lab Bhattacharjee
120 Points
										
$$\sec^2y-\tan^2y=1$$ $$\implies\dfrac{1+\sec y-\tan y}{1+\sec y+\tan y}$$ $$=\dfrac{\sec^2y-\tan^2y+\sec y-\tan y}{1+\sec y+\tan y}$$ $$=\sec y-\tan y=\dfrac{1-\sin y}{\cos y}$$
2 years ago
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