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```
how 2 solve dis...??

1+(1+(1/2))+(1+(1/2)+(1/4))+.......to n terms
plz ...plz ...tell me dis..```
7 years ago

Prudhvi teja
83 Points
```										Dear srishtisum of nterms can be written as  as n+n-1/2 + n-2/4-----+1/2n-1which is sum of nterms of an AGPThe sum Sn of first n terms of an A.G. P. is obtained in the   following way : Sn = ab + (a + d)br + (a + 2d)br2 +.........+(a + (n - 2)d)brn-2 + (a + (n - 1)d)brn-1 Multiply both sides by r, so that r Sn = abr + (a + d)br2+.........+(a + (n - 3)d)brn-2 + (a + (n - 2)d)brn-1 + (a + (n - 1)d)brn Subtracting, we get (1 - r)Sn = ab + dbr + dbr2 +.......+dbrn - 2 + dbrn - 1 - (a + (n - 1)d)brn = ab + dbr/(1–rn–1)/(1–r) – (a+(n–1)d)brn => Sn = ab/1–r + dbr(1–rn–1)/(1–r)2 – (a+(n–1)d)brn/1–r a=n
b=1
r=.5
d=-1
So Sn = 2n+(-1)*0.5*1(1-0.5n-1)*4-2n
=>Sn = 2n-2(1-0.5n-1)-2n

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7 years ago
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