Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        Two bodies of masses m1 and m2 and specific heat capacities s1 and s2 are connected by a rod of length l, cross-sectional area A, thermal conductivity K and negligible heat capacity. The whole system is thermally insulated. At time t = 0, the temperature of the first body is T1 and the temperature of the second body is T2(T2 > T1). Find the temperature difference between the two bodies at time t.`
3 years ago

Kevin Nash
332 Points
```										Sol. dθ/dt = 60/10 * 60 = 0.1°C/sec
dQ/dt = KA/d (θ base 1 – θ base 2)
= KA * 0.1/d + KA * 0.2/d + ………+ KA * 60/d
= KA/d (0.1 + 0.2 + ………+ 60) = KA/d * 600/2 * (2 * 0.1 + 599 * 0.1)
[∴ a + 2a + ………+ na = n/2{2a + (n - 1)a}]
= 200 * 1 * 10^-4/20 * 10^-2 * 300 * (0.2 + 59.9) = 200 * 10^-2 * 300 * 60.1/20
= 3 * 10 * 60.1 = 1803 w = 1800 w

```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Thermal Physics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
Get extra Rs. 413 off
USE CODE: COUPON10
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details
Get extra Rs. 445 off
USE CODE: COUPON10

Post Question