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Shane Macguire Grade: upto college level
`        The pressure of a gas changes linearly with volume from 10 kPa, 200 cc to 50 kPa, 50 cc. (a) Calculate the work done by the gas. (b) If no heat is supplied or extracted from the gas, what is the change in the internal energy of the gas?`
3 years ago

Deepak Patra
474 Points
```										Sol. P base 1 = 10 kpa = 10 × 10^3 pa. P base 2 = 50 × 10^3 pa. v base 1 = 200 cc. v base 2 = 50 cc
(i) Work done on the gas = ½ (10+50) x 10^3 x (50-200) x 10 ^-6 = - 4.5 J
(ii) dQ = 0 ⇒ 0 = du + dw ⇒ du = – dw = 4.5 J

```
3 years ago
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