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`        A calorimeter contains 50 g of water at 50°C. The temperature falls to 45°C in 10 minutes. When the calorimeter contains 100 g of water at 50°C. it takes 18 minutes for the temperature to become 45°C. Find the water equivalent of the calorimeter.`
3 years ago

Kevin Nash
332 Points
```										Sol. Let the water eq. of calorimeter = m
(m + 50 * 10^-3) * 4200 * 5/10 = Rate of heat flow
(m + 100 * 10^-3) * 4200 * 5/18 = Rate of flow
⇒ (m + 50 * 10^-3) * 4200 * 5/10 = (m + 100 * 10^-3) * 4200 * 5/18
⇒ (m + 50 * 10^-3) 18 = 10m + 100 * 10^-3
⇒ 18m + 18 * 50 * 10^-3 = 10m + 1000 * 10^-3
⇒ 8m = 100 * 10^-3 kg
⇒ m = 12.5 * 10^-3 kg = 12.5 g

```
3 years ago
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