A 0.1 kg steel ball falls from a height of 10m on the ground and rebounds to a height of 7m. If the dissipated energy remains in the ball in the form of heat then by how much will the temperature of the ball be raised

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Akash · Answer

Mgh=ms[T2-T1] Gh=s[T2-T1] Gh=9.8*3=29.4J S=110 cal 1cal=4.2J 110cal=462J [T2-T1]=29.4/462 [T2-T1]=0.064C 110cal=110*4.2J 110cal=

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A 0.1 kg steel ball falls from a height of 10m on the ground and rebounds to a height of 7m. If the dissipated energy remains in the ball in the form of heat then by how much will the temperature of the ball be raised

A 0.1 kg steel ball falls from a height of 10m on the ground and rebounds to a height of 7m. If the dissipated energy remains in the ball in the form of heat then by how much will the temperature of the ball be raised

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A 0.1 kg steel ball falls from a height of 10m on the ground and rebounds to a height of 7m. If the dissipated energy remains in the ball in the form of heat then by how much will the temperature of the ball be raised

A 0.1 kg steel ball falls from a height of 10m on the ground and rebounds to a height of 7m. If the dissipated energy remains in the ball in the form of heat then by how much will the temperature of the ball be raised

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