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A pendulum clock gives correct time at 20 degree Celsius at a place where g= 9.800 m/s^2. The pendulum consists of a light steel rod connected to a heavy ball. It is taken to a different place where g=9.788 m/s^2. At what temperature will it give correct time?coefficient of linear expansion of steel = 12x 10^-6/ degree celsius.
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7 years ago

28 Points
```										Dear Cathy,
Ans: The time period is T=2∏√(L/g)
So if the time period is the same then we get,
T=constant hence L1/L2=g1/g2
Now as the value of g is decreasing and hence temp must be decreased to get the same value of T. Now L2=L1(1-αt)
solving we get,
t= -122 degree
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All the best Cathy !!!

Regards,
```
7 years ago
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