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```				   THE VOLUME OF AIR BUBBLE IS DOUBLED WHEN IT RISES FROM BOTTOM OF LAKE TO ITS SURFACE. THE ATMOSPHERIC PRESSURE IS 75CM OF MERCURY AND RATIO OF DENSITY OF MERCURY TO THAT OF LAKE IS 40/3.
FIND THE DEPTH OF THE WATER.
```

6 years ago

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```										Dear Akhil Killawala,
Ans:- The pressure at the bottom of the lake is = The pressure due to hte air + The pressure due to the water column=P1
The pressure at the top is only the atmosphereic pressure=P2 Initial Vol=V1 and final Vol is =V2
NOW YOU HAVEN'T MENTIONED ABOUT THE TEMP SO I AM CONSIDERING IT TO BE CONSTANT
So from gas eq we get P1V1=P2V2
V2=2V1
Putting the values in the eq 1 we get,
H=10 meter
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.
All the best Akhil Killawala !!!

Regards,
```
6 years ago

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