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Vishnu Saran Grade: 10
        

Hot water of mass 0.35kg at 80degrees celsius is poured into a copper cup which is initially at 25 degrees celsius. The mass of the cup is 0.80kg. Assume that no energy is lost to the surroundings.


Give - Specific Heat Capacity of water = 4200Jkg-1C-1


         Specific Heat Capacity of Copper = 400Jkg-1C-1


Question)  Find the initial Temperature of water.


 


Thanks,


Vishnu

7 years ago

Answers : (1)

Rohith Gandhi
24 Points
										

Dear Vishnu,


since no energy is lost to surroundings


heat lost by water = heat gained by copper cup


let final common temperature of the mixture = T


therefore,


0.35X4200X(80-T) = 0.8X400X(T-25)


117600-1470T = 320T-8000


=> 117600+8000 = 1470T+320T


125600=1790T


=>T = 125600/1790 = 70.16 degree C


final common temperature of mixture = 70.16 degree C


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Regards,

Askiitians Experts

Rohith Gandhi P

7 years ago
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