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pallavi pradeep bhardwaj Grade: 12
        An object is at temp of 400 degree celcius.At what temp would it radiate energy twice as fast?The temp of the surroundings may be as sumed to be negligible
7 years ago

Answers : (1)

AskIITians Expert Hari Shankar IITD
17 Points
										

By STefan-Boltzmann law, Rate of heat radiation E is proportional to T4 .


Let E = kT4.


Also, let the iniotial energy radiated be E1.


Temperature T = 400 C = 400+273 K = 673 K


So, E1 = k (673)4 .................(1)


Let rate of heat radiation be 2E1 at temperature T2.


Then, 2E1 = k(T2)4


2E1 = [E1/(673)4] (T2)4 using (1)


(T2)4 = 2 (673)4


T2 = (2)1/4 * 673 = 1.19 * 673 = 800.33 K


 

7 years ago
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