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`        Hot water cools from 60degree celcius to 50 degree celcius in the first 10 min and to 42 degree celcius in the next 10 min .The temp of the surrounding.`
8 years ago

Ramesh V
70 Points
```										average temp. in first case = (60+50) /2 = 55 C
average temp. in second case = (50+42) /2 = 51 C
as frm law of cooling
dT/dt = -k(T-To )  where To is temp. of surrounding
case 1 : dT = 10 C and dt = 10 mins
so ,  1=-k(55-To )         ....(1)
case 2 : dT = 8 C and dt = 10 mins
so ,  0.8=-k(51-To )       .........(2)
From 1 and 2 , we have
Temp of surr. as 35 C
--
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8 years ago
Visalakshi Senthil Kumar
24 Points
```										Excuse sir I need to correct u in the second step ie., (50+42)/2=46 So the room temp would be 10C    dT/dt=0.8=-k (46-t)dT2/dt2 =k (55-t)Dividing them both we get1/0.8=(55-t)/(46-t)Therfore t=10Answer by Aswath S, AECS PU College, Bangalore FiitjeeFuture IIT ian     ha ha ha
```
one year ago
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