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pallavi pradeep bhardwaj Grade: 12
        Hot water cools from 60degree celcius to 50 degree celcius in the first 10 min and to 42 degree celcius in the next 10 min .The temp of the surrounding.
8 years ago

Answers : (2)

Ramesh V
70 Points
										

average temp. in first case = (60+50) /2 = 55 C


average temp. in second case = (50+42) /2 = 51 C


as frm law of cooling


dT/dt = -k(T-To )  where To is temp. of surrounding


case 1 : dT = 10 C and dt = 10 mins


so ,  1=-k(55-To )         ....(1)


case 2 : dT = 8 C and dt = 10 mins


so ,  0.8=-k(51-To )       .........(2)


From 1 and 2 , we have


Temp of surr. as 35 C


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Naga Ramesh

IIT Kgp - 2005 batch


 


 

8 years ago
Visalakshi Senthil Kumar
24 Points
										
Excuse sir I need to correct u in the second step ie., (50+42)/2=46 
So the room temp would be 10C    
dT/dt=0.8=-k (46-t)
dT2/dt2 =k (55-t)
Dividing them both we get
1/0.8=(55-t)/(46-t)
Therfore t=10
Answer by Aswath S, AECS PU College, Bangalore Fiitjee
Future IIT ian     ha ha ha
one year ago
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