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        A body is just floating in a liquid ( their densities are equal ). What will happen to the body if it is slightly pressed and released ? Why ?
6 years ago

SAGAR SINGH - IIT DELHI
879 Points
										Dear student,
Assuming Archimedes' principle to be reformulated as follows,
$\mbox{apparent immersed weight} = \mbox{weight} - \mbox{weight of displaced fluid}\,$
then inserted into the quotient of weights, which has been expanded by the mutual volume
$\frac { \mbox{density}} { \mbox {density of fluid} } = \frac { \mbox{weight}} { \mbox {weight of displaced fluid} } \,$,
yields the formula below. The density of the immersed object relative  to the density of the fluid can easily be calculated without measuring  any volumes:
$\frac { \mbox {density of object}} { \mbox {density of fluid} } = \frac { \mbox {weight}} { \mbox {weight} - \mbox {apparent immersed weight}}\,$

All the best.
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Sagar Singh
B.Tech, IIT Delhi


6 years ago
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