MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
chua kok tong Grade: Upto college level
        

I read in the book the derivation of pv=nrt, they relate the change of momentum and consider time it take for 1 collision. However, if considering a cubical volume expand at the speed that is faster than the speed of the gas molecule so that the gas molecule wont collide with the wall(i don't know if this is possible or not). At that particular instant the volume may have a volume of V while the gas havent touches the wall of the container(in this case work is done by external sources in expanding the volume of the cube). At this time, is it obey pv=nRT and can take p1v1=p2v2?(cause if this can be happen and no collision occur at the wall the pressure exert on the wall is 0)?

6 years ago

Answers : (3)

AJIT AskiitiansExpert-IITD
68 Points
										

Dear  chua ,


if you are considering the gas to expand slowly than container than it actually is like as if gas is in free space as no molecule can collide to wall. it is like an expandable space. and the pv =nrt holds for that . so it shall continue to hold. why it holds in space  when it is derived in a container  ?  because we assume that at infinity there is a container and apply the results.  Now in your case no one can apply work continuously to the wall  as energy is finite and so wall shall meet the molecule at infinity and so it is actually not a feasible sitiuation.


 


Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.


All the best.


Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.


Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar  respectively : Click here to download the toolbar..


Askiitians Expert


Ajit Singh Verma IITD


 

6 years ago
Aman Bansal
592 Points
										

dear chua kok tong,


ACTUALLY THIS IS A HYPOTHETICAL SITUATION


BUT STILL IN MY OPINION ALL YOUR SUPPOSITIONS ARE CORRECT AND THE CONDITION SEEMS TO BE TRUE...



We are all IITians and here to help you in your IIT JEE preparation.



Now you can win



exciting gifts

by answering the questions on Discussion Forum. So help discuss any

query on askiitians forum and become an Elite Expert League askiitian.



Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar :






Click here





to download the toolbar..



AMAN BANSAL

6 years ago
chua kok tong
29 Points
										

Anyway the P at the formula is the pressure exert by gas on the container?

6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: R 2,600
  • View Details
  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details