When a certain amount of ethylene was burnt 6226kj heat was evolved. If heat of combustion of ethylene is 1411 kj then the volume of Oxygen at NTP that entered in reaction is ??

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c2h4+3o2------>2co2+2h2o moles of o2 reacted=(6226/1411)*3 vol. of o2 reacted at STP=(6226/1411)*3*22.4=296.5 ltrs

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When a certain amount of ethylene was burnt 6226kj heat was evolved. If heat of combustion of ethylene is 1411 kj then the volume of Oxygen at NTP that entered in reaction is ??

When a certain amount of ethylene was burnt 6226kj heat was evolved. If heat of combustion of ethylene is 1411 kj then the volume of Oxygen at NTP that entered in reaction is ??

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When a certain amount of ethylene was burnt 6226kj heat was evolved. If heat of combustion of ethylene is 1411 kj then the volume of Oxygen at NTP that entered in reaction is ??

When a certain amount of ethylene was burnt 6226kj heat was evolved. If heat of combustion of ethylene is 1411 kj then the volume of Oxygen at NTP that entered in reaction is ??

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