When 40 cc of slightly moist hydrogen chloride gas is mixed with 20 cc of ammonia gas the final volume of gas at the same temperature and pressure will be?

Question

Samridhi · Answer

Volume will be same as 20 cc as NH3 is limiting ....HCl + NH3 = NH4Cl Which is totally balanced So HCl should also be 20cc ...HCl interacted = 40-20 = 20 cc U can solve this by calculating moles also but this would only lead to complicated calculations ...

Samridhi · Answer

Sorry ...it`s unreacted above instead of interacted.... I think it would help you you can search for Avogadro`s hypothesis to understand more clearly ....that would make u clear ....

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When 40 cc of slightly moist hydrogen chloride gas is mixed with 20 cc of ammonia gas the final volume of gas at the same temperature and pressure will be?

When 40 cc of slightly moist hydrogen chloride gas is mixed with 20 cc of ammonia gas the final volume of gas at the same temperature and pressure will be?

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When 40 cc of slightly moist hydrogen chloride gas is mixed with 20 cc of ammonia gas the final volume of gas at the same temperature and pressure will be?

When 40 cc of slightly moist hydrogen chloride gas is mixed with 20 cc of ammonia gas the final volume of gas at the same temperature and pressure will be?

2 Answers

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