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what volume of chlorine at stp is required to liberate all iodine from 200ml of 0.2M KI solution

what volume of chlorine at stp is required to liberate all iodine from 200ml of 0.2M KI solution

Grade:11

1 Answers

Bristi Mukherjee
12 Points
6 years ago
2KI + Cl2  ------->  2KCl + I2
Moles of KI reacted = 0.2 x 200/1000 = 0.04 moles of KI
According to reaction stoichiometry, 0.04moles of KI will react with 0.04/2 moles Cl2  to liberate I2 completely.
At STP, 1 mole Cl2 corresponds to 22.4L
So, 0.02 moles of Cl2  corresponds to 0.448L
 
Hence 0.448L of Cl2 will be required to liberate I2 completely from the given solution

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