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What volume of chlorine at STP is required to liberate all iodine from 200ml of 0.2M KI solution?

What volume of chlorine at STP is required to liberate all iodine from 200ml of 0.2M KI solution?

Grade:11

1 Answers

Vikas TU
14149 Points
6 years ago
Dear Student,
200 ml of 0.2 M KI arrangement has 0.2/5= 0.04 mol KI 
Here the adjusted condition is 
2KI+ Cl2 = 2KCl + I2 
In this way, for 2 moles KI there is need of 1 mole Cl2 
For 0.04 mole it is 0.02 mole 
Volume is 0.02x22.4 lit = 0.448 lit (STP).
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)

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