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what is the oxidation state of sulphur in H 2 S 2 O 8, Na 2 S 4 O 8 and Na 2 S 2 O 3.

what is the oxidation state of sulphur in H2S2O8,
Na2S4Oand Na2S2O3.

Grade:11

9 Answers

Umakant biswal
5349 Points
7 years ago
@ bhavika 
in H2S2O8, since 2 oxygen is forming the peroxide linkage here , so, the o.n of sulpher will be +6 . and in the 2nd case NA2S4O8 , in thaat case take sulpher o.n to be x 
after that , 2(1) +4(x) + 8 (-2) =0 
so, by calculating the value of x u will get sulpher will present in a oxidation state of 3.5 
coming to the 3rd case in na2s2o3, 
take that in pieces and calculate the oxidation number , 
u know , na hv a o.n of +1 , as there are two , so, it will be +2 , 
now , oxygen is -2 , there are 3 atoms , so, that will be -6 , 
so, u need to balance a +4 in it , thatswhat u left with , and there are 2 sulpher left , 
so, each one hv a +2 charge . 
SO, THE O.N OF SULPHER HERE IS +2 . 
HOPE IT CLEARS YOUR DOUBT 
ALL THE BEST ...
 
bhavika
26 Points
7 years ago
but hou do i know that give compound has peroxy linkage.
i think that is concluded by drawing structure only . i am not able to draw thw structure.
Umakant biswal
5349 Points
7 years ago
u need to remember that which structure have peroxide linkage and which structure have not , 
there are only some exception with peroxide linkage , 
go through the ncert redox reaction chapter solved example , then start solving exercise . 
ALL THE BEST /..
Pranav Dabhade
34 Points
7 years ago
u need to remember that which structure have peroxide linkage and which structure have not , 
there are only some exception with peroxide linkage .
AKHILESH
12 Points
7 years ago
In H2S2O8 , oxidation state of sulphur would be like this2(+1) +2x +8(-2)=0For which x comes out to be +7.
AKHILESH
12 Points
7 years ago
But oxid state of sulfur cant be more than 6, hence it definitely +6 no matter of what it is coming after solving the eqn.
Suman shekhar
11 Points
7 years ago
If the calculated o no.comes more than max o no. Then definitely there is peroxylinkage.if clcltd o no. Comes less than max then it is the required one.if equal to max than there is oxy linkage.
Sneh Agrawal
29 Points
6 years ago
Since in H2S2O8 calculated oxidation state is +7 which is more than the maximum oxidation state of sulphur.This implies that the compound must have a peroxide linkage.All the best:)
Puja
13 Points
5 years ago
First calculate the oxidation number 
Case
1- if oxidation number is equal to group number then must have C.A-B.A-C A(That means central atom bond with bonded atom then with central atom)
2-if oxidation number is greater than group number than peroxy linkage is must
3-if oxidation number is less than group number then C.A-C.A
 
3-if oxidation number is less than group number then C.A-C.A

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