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Also, the final pressure in both the flask Pa and Pb will be same i.e.,Pa = Pb = Pand alsoVa = Vb = V.
UsingIdeal Gas Lawfor the combined system initially, we have
PV = nRT
⇒ 0.5 * 2V = 0.7 * R * 300.15 …[both the flasks have the same volume]
⇒V = 210.105 R….. (i)
For flask a :
Pa * Va = na * R * Ta
⇒ P * V = na * R * Ta
⇒ P * 210.105 R = na * R * 400.15 ….. [ value of V from (i)]
⇒na = 0.525P….. (ii)
For flask b:
Pb * Vb = nb * R * Tb
⇒ nb = (Pb Vb) / (R Tb)
⇒ nb = (P * 210.105 R) / (R * 300.15 )
⇒nb = 0.7P….. (iii)
We know,
Total no.of moles initially was = na + nb
Substituting values of na and nb from (ii) & (iii)
⇒ 0.7 = 0.525P + 0.7P
⇒ 0.7 = 1.225 P
⇒P= 0.7 / 1.225 =0.5714 atm
∴na = 0.525P = 0.525 * 0.5714 = 0.299 mol ≈ 0.3 mol
And,
nb = 0.7P = 0.7 * 0.5714 = 0.399 mol ≈ 0.4 mol
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