Guest

The wavelength of the radiation emitted when an electron falls from Bohr’s orbit 4 to 2 in hydrogen atom is

The wavelength of the radiation emitted when an electron falls from Bohr’s orbit 4 to 2 in hydrogen atom is

Grade:11

1 Answers

Kaustubh Mishra
11 Points
6 years ago
As we know the formula (Wavelength)^–1 = RZ^2 [(1/n1^2) – (1-n2^2)]Here, R = Rhydbergs Constant = 109677cm N1 =4 , N2=2. Z=1 (since it is hydrogen atom)By plugging these values in the formula we get Wavelength^-1 = 20564.43So wavelength = 0.0000486 cms OR 0.000000486 m OR 4.86 x10 ^-7 m

Think You Can Provide A Better Answer ?

ASK QUESTION

Get your questions answered by the expert for free