The volume of a gas in discharge tube is 1.12×10^-7 ml at stp then the no of molecule of gas in a tube is

Question

Vikas TU · Answer

Dear Student,

At STP, a volume of 22400 mL is occupid by 6.023*1023 particles of any gas.

In this way, 1.12 * 10-7mL is possessed
by 6.023*1023 *1.12 * 10-7*22400-1 moleules or 3.0115 * 1012 molcules.

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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The volume of a gas in discharge tube is 1.12×10^-7 ml at stp then the no of molecule of gas in a tube is

The volume of a gas in discharge tube is 1.12×10^-7 ml at stp then the no of molecule of gas in a tube is

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The volume of a gas in discharge tube is 1.12×10^-7 ml at stp then the no of molecule of gas in a tube is

The volume of a gas in discharge tube is 1.12×10^-7 ml at stp then the no of molecule of gas in a tube is

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