the separation between a point source of light on a screen is increased by 1.5 % , the percent change in the intensity is?

Question

Limra · Answer

The intensity follows an inverse metre relationship so I is equal to 1 by m square hence the percentage change in intensity will be 1.5 square inverse which is 2.55 approximately equal to 3% decrease

Esha chopra · Answer

Intensity is inversely proportional to the sq. Of the distance therefore approx. It will fetch you an answer of 3%

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the separation between a point source of light on a screen is increased by 1.5 % , the percent change in the intensity is?

the separation between a point source of light on a screen is increased by 1.5 % , the percent change in the intensity is?

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the separation between a point source of light on a screen is increased by 1.5 % , the percent change in the intensity is?

the separation between a point source of light on a screen is increased by 1.5 % , the percent change in the intensity is?

2 Answers

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