The rate of first-order reaction is 0.04 mol/L/sec at 10 minutes and 0.03mol/L/sec at 20 minutes after initiation.Find the half-life of the reaction.

Question

Sunil Kumar FP · Answer

half-life of the reaction.

Bharat Makkar · Answer

THANKS SIR....!!

patti mounika · Answer

the rate of a1st order reaction is0.04 mollit-1sec-1 at10sec and 0.03 at 20sec after intiation of the reaction .the half life period of the reaction

Giri Dharan · Answer

Given :-T1= 10sT2= 20sRi= 0.04Rf= 0.03Formula:- T1/2= 0.693 / k K= 2.303 log(Ri/Rf) / T2-T1K= 2.303 log (4/3) / 20-10K= 2.303×0.13 / 10K= 0.0299T1/2= 0.693 / kT1/2= 0.693 / 0.0299T1/2= 23.1

rani · Answer

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Yash · Answer

Sir why have you multiplied by 20 instead of 10 mins (the interval between the two rates we are considering)????????

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The rate of first-order reaction is 0.04 mol/L/sec at 10 minutes and 0.03mol/L/sec at 20 minutes after initiation.Find the half-life of the reaction.

The rate of first-order reaction is 0.04 mol/L/sec at 10 minutes and 0.03mol/L/sec at 20 minutes after initiation.Find the half-life of the reaction.

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The rate of first-order reaction is 0.04 mol/L/sec at 10 minutes and 0.03mol/L/sec at 20 minutes after initiation.Find the half-life of the reaction.

The rate of first-order reaction is 0.04 mol/L/sec at 10 minutes and 0.03mol/L/sec at 20 minutes after initiation.Find the half-life of the reaction.

6 Answers

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