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The radius of a divalent cation m2+ is 94 pm and of divalent anion X–2 is 146 pm. Thus mx has :(

 The radius of a divalent cation m2+ is 94 pm and of divalent anion X–2 is 146 pm. Thus mx has :(

Grade:12th pass

1 Answers

Umakant biswal
5349 Points
7 years ago
@ piyush
The radius of MX compound will be equal to some of the radius of M2+ cation and the radius of X2- anion. 
so, It will be 94+146= 240pm
HOPE IT CLEARS YOUR DOUBT 
ALL THE BEST ..

 

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