the pressure of iodine gas at 1273k, is 0.112 .where as the expected pressure is 0.073.what is the increase in pressure?

Question

Vikas TU · Answer

Increase in pressure would be obvious the subtraction of the two pressures. Hence the increase in pressure => 0.112 – 0.073 = > 0.039 atm.

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the pressure of iodine gas at 1273k, is 0.112 .where as the expected pressure is 0.073.what is the increase in pressure?

the pressure of iodine gas at 1273k, is 0.112 .where as the expected pressure is 0.073.what is the increase in pressure?

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the pressure of iodine gas at 1273k, is 0.112 .where as the expected pressure is 0.073.what is the increase in pressure?

the pressure of iodine gas at 1273k, is 0.112 .where as the expected pressure is 0.073.what is the increase in pressure?

1 Answers

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