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the oxidation number Cr is +6 in FeCr 2 O 4, FeCrO 4 , Cr 2 (SO 4 )O 3 , [Cr(OH) 4 ] -

the oxidation number Cr is +6 in     
FeCr2O4, FeCrO4, Cr2(SO4)O3, [Cr(OH)4]-

Grade:11

2 Answers

Sakshi
askIITians Faculty 652 Points
8 years ago
Hey Student..
As per what is required in this question, you need to take into account the basics of general oxidation states. As for example O has -2, H as +1, Fe as +2 or +3 according to the ligands so present..
just take into account this hint and try calculating the oxidation state..
PASUPULETI GURU MAHESH
126 Points
8 years ago
THE ANSWER IS  FeCrO4  SINCE THE OXIDATION STATE OF FE=+2,
CR =x, O=-2
THEN  (+2)+(x)+4(-2)=0
          x-6=0
         x=6
 
THERE FORE OXIDATION STATE OF  CR  =6   IN FeCrO4
     HENCE PROVED . THANK YOU

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