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the no. of moles of hydroxide ions in 0.3litre of 0.005M solution of Ba(OH)2 is

the no. of moles of hydroxide ions in 0.3litre of 0.005M solution of Ba(OH)2  is

Grade:12th pass

3 Answers

Ashish Kumar
106 Points
7 years ago
By the formula- Molarity=Moles of solute/Volume of solution we get the moles of solute is 0.0013 moles. Now the volume of water is 0.3L. The volume of 0.0013 moles of Ba(OH)2 equals to 0.0013 x 22.4L= 0.029L. Therefore the volume os solvent i.e. water = 0.3L- 0.029L=0.271L. Now 22.4L is the volume of 1 mole of water so by unitary method we get the volume of 0.271L of water= 0.271/22.4=0.0121 moles.
Now moles of Ba(OH)2 =0.0013. In 1 molecule of the compound there are 2 molecules of hrdroxide ions so the number of moles of hydroxide ions= 0.0013 x 2 =0.0026.
aMoles of water =0.0121 moles. 1 molecule of water has 1 H+ ion and 1 OH- ion so moles of OH- ions gained from water = 0.0121 x 1 =0.0121 moles.
Therefore total moles of hydroxide ions = 0.0026+0.0121=0.0147 Moles
Hithesh seedarla
35 Points
7 years ago
Ba(OH)2=0.005M, in 0.03litre no.of moles of (OH-)=?       
sol: M=n/v  in litres 
0.05 =n/o.3
0.05×0.3=n
n(OH-)=0.0015
Mohammed Mushthaq
11 Points
6 years ago
1M of a solution means , 1L of the solution contain 1 mole of solute.Hence the given solution contains 0.005 moles of Ba (OH)2 in 1L. So,there will be 0.0015 (0.005×0.3) moles of Ba (OH)2 in 0.3 L of the solution.1 mol Ba (OH)2 contains 2 mol of OH-.Hence,0.0015 mole contains 0.003 moles of OH- ion. Hope this helps.

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